error: ‘uint16_t’ does not name a type

清泛网 · 发表于 2015-10-16 16:17:24

#include <stdint.h> 解决。

/**
* @file stdint.h
*
* Permission is hereby granted, free of charge, to any person obtaining a
* copy of this software and associated documentation files (the "Software"),
* to deal in the Software without restriction, including without limitation
* the rights to use, copy, modify, merge, publish, distribute, sublicense,
* and/or sell copies of the Software, and to permit persons to whom the
* Software is furnished to do so, subject to the following conditions:
*
* The above copyright notice and this permission notice (including the next
* paragraph) shall be included in all copies or substantial portions of the
* Software.
*
* THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
* IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
* FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
* AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
* LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
* FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER
* DEALINGS IN THE SOFTWARE.
*/
/* Created by Danny Smith <danny_r_smith_2001@yahoo.co.nz> */
#ifndef _STDINT_H
#define _STDINT_H
#pragma GCC system_header
#include <_mingw.h>
/* ISO C9x 7.18 Integer types <stdint.h>
* Based on ISO/IEC SC22/WG14 9899 Committee draft (SC22 N2794)
*/
#define __need_wint_t
#define __need_wchar_t
#include <stddef.h>
/* 7.18.1.1 Exact-width integer types */
typedef signed char int8_t;
typedef unsigned char uint8_t;
typedef short int16_t;
typedef unsigned short uint16_t;
typedef int int32_t;
typedef unsigned uint32_t;
typedef long long int64_t;
typedef unsigned long long uint64_t;

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error: ‘uint16_t’ does not name a type

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